3x^2-32x-176=0

Solution for 3x^2-32x-176=0 equation:

3x^2-32x-176=0

a = 3; b = -32; c = -176;
Δ = b2-4ac
Δ = -322-4·3·(-176)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-56}{2*3}=\frac{-24}{6}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+56}{2*3}=\frac{88}{6}
=14+2/3
$